how to load my own $row with $output

angga777

Member

Posted 17 October 2012 - 17:39 PM

I have a query:

Example:



$this->db->where('island.id_island',$this->uri->segment(3));

	    $data['query']=$this->db->get('island');

view:



<?php foreach($query->result()as $row): ?>

<?=$row->island_name?>

<?php endforeach; ?>

I want to display it with $output view. how to render it?

victor

Member

Posted 17 October 2012 - 17:57 PM



...

//controller

$output = $crud->render();

$this->data['crud'] =(array)$output;



$this->data['category'] = //get categories........;

$this->load->view('your_template',$this->data);



....



// veiw

........

<div>

<?=$crud['output']; ?>

</div>

<div>

<div>

<?if($category):foreach($category as $item):?>

<?=$itemp['title']?>

<?endforeach; endif;?>

</div>

angga777

Member

Posted 24 October 2012 - 08:56 AM

still doesn't work, pal..

js_file, css_file and my query Undefined

victor

Member

Posted 25 October 2012 - 10:37 AM

show,please, controller's code and view

David Leiva

Member

Posted 26 October 2012 - 16:29 PM

I think you are not using grocery crud properly. Look at the examples how it works.

You should do:

[php]
// in your controller
$crud = new grocery_CRUD();
$crud->set_table('island');
$crud->where('island.id_island',$this->uri->segment(3));
$crud->colums('island_name')
$output = $crud->render()

//in your view
echo $output;
[/php]

angga777

Member

Posted 01 November 2012 - 03:11 AM

My controller



function multiupload()

{

			    $this->load->library('Image_CRUD');

			    $image_crud = new Image_CRUD();

			   

			    $image_crud->set_table('images');

 

			    $image_crud->set_primary_key_field('id');

			    $image_crud->set_url_field('url');

			    $image_crud->set_title_field('title');

 

                $image_crud->set_relation_field('id_island')

			    ->set_ordering_field('priority')

			    ->set_image_path('assets/uploads/img');

 

			    echo '<h2>Upload Photo</h2>';

 

			    $output = $image_crud->render();

			   

			    $this->_upload_output($output);

}



function _upload_output($output = null)

    {

       		

        $this->data['crud'] =(array)$output;



        

        $this->db->where('island.id_island',$this->uri->segment(3));

        

        $this->data['category'] = $this->db->get('island');

        $this->load->view('upload_view.php',$this->data);		   



    }

My View





<!DOCTYPE html>

<html>

<head>

    <meta charset="utf-8" />



<?php

foreach($css_files as $file): ?>

    <link type="text/css" rel="stylesheet" href="<?php echo $file; ?>" />

<?php endforeach; ?>



<?php foreach($js_files as $file): ?>

    <script src="<?php echo $file; ?>"></script>

<?php endforeach; ?>



</head>

<body>

    

        <a href='<?php echo site_url('main_adm/island_management')?>'><b> <<-- back </b></a>

        <br><br>

    <?if($category):foreach($category as $item):?>

    <?=$itemp['island_name']?>

    <?endforeach; endif;?>



    <div>

   	

     <?=$crud['output']; ?>





    </div>

    

</body>

</html>

where is my mistake? can you help vict?